transforming a parabola
Practise transforming a parabola with an original VectorPaths question, worked explanation and related VCE Methods practice.
3 practice marks
Original practice question
The graph of $y=x^2$ is transformed into $y=3 \left(x + 1\right)^{2} - 4$. State the transformations, the vertex and the range.
Worked explanation
- Read the transformations
Stretch vertically by factor 3. Translate horizontally by -1 and vertically by -4 (signed distances).
- Find the vertex
The squared term is zero at $x=-1$, giving vertex $(-1,-4)$.
- Use the opening direction
The coefficient is 3, so the range is $[-4,\infty)$.
Vertex $(-1,-4)$; range $[-4,\infty)$.
Original VectorPaths practice; not an official VCAA question or marking rubric.