function evaluation
Practise function evaluation with an original VectorPaths question, worked explanation and related VCE Methods practice.
1 practice marks
Original practice question
Let $g(x) = \dfrac{-x - 2}{x + 3}$. Find $g(-1)$.
Worked explanation
- Substitute x = -1 into f(x)
\[f(-1) = \dfrac{-(-1) - 2}{(-1) + 3}\]
- Calculate the result
\[f(-1) = - \frac{1}{2}\]
-1/2
Original VectorPaths practice; not an official VCAA question or marking rubric.