stationary points
Practise stationary points with an original VectorPaths question, worked explanation and related VCE Methods practice.
3 practice marks
Original practice question
Find the turning points of $y = -2x^2 + 6x + 3$ and classify each as a maximum or minimum.
Worked explanation
- Find f'(x)
\[f'(x) = 6 - 4 x\]
- Find stationary points
\[x = \frac{3}{2}\]
- Use second derivative test
\[(\frac{3}{2}, \frac{15}{2}) \text{ is a local maximum}\]
\[(\frac{3}{2}, \frac{15}{2}) \text{ is a local maximum}\]
Original VectorPaths practice; not an official VCAA question or marking rubric.