polynomial equation
Practise polynomial equation with an original VectorPaths question, worked explanation and related VCE Methods practice.
2 practice marks
Original practice question
Find all values of $x$ such that $x^{3} - 6 x^{2} + 9 x = 0$.
Worked explanation
- Factor the polynomial
\[x^{3} - 6 x^{2} + 9 x = x \left(x - 3\right)^{2}\]
- Set each factor to zero
\[x = 0, x = 3\]
[0, 3]
Original VectorPaths practice; not an official VCAA question or marking rubric.